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因式分解m^3-2m^2n+mn^2-4m^2+4mn+4m
人气:114 ℃ 时间:2020-06-05 02:58:20
解答
m^3-2m^2n+mn^2-4m^2+4mn+4m
=m(m^2-2mn+n^2-4m+4n+4)
=m[(m-n)^2-4(m-n)+4]
=m(m-n-2)^2
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