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若(SinA+COSA)/(SinA-CosA)=2.则Sin(180度+A)Cos(180-A)=?
人气:183 ℃ 时间:2020-05-01 18:54:20
解答
Sin(180度+A)Cos(180-A)= -sin(A) * -cos(A) = sin(A)cos(A)另一方面:(SinA+COSA)/(SinA-CosA)=2 ===〉(SinA+COSA) = 2(SinA-CosA)两边平方:[sin(A)]^2 + [cos(A)]^2 + 2sin(A)cos(A) =4[sin(A)]^2 + 4[cos(A)]^2 ...
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