将下列三角函数转化为锐角三角函数 特别急!急啊!
sin623°42`=sin(-3π/5)=tan3π/5cos(-11π/9)=
cos(-104°26`)= tan17π/6
人气：459 ℃ 时间：2020-05-21 23:41:10
解答
sin623°42`= -sin83°42`
sin(-3π/5)= -sin72°
tan3π/5=-tan72°
cos(-11π/9)=-cos40°
cos(-104°26`)= -cos14°26`
tan17π/6=-tan30°
推荐
猜你喜欢
