[（3-1）×2+1]×
| 3 |
| 3+7 |
=[2×2+1]×
| 3 |
| 3+7 |
=5×
| 3 |
| 10 |
=1
| 5 |
| 10 |
第四次相遇甲跑了：
[（4-1）×2+1]×
| 3 |
| 3+7 |
=[3×2+1]×
| 3 |
| 10 |
=7×
| 3 |
| 10 |
=2
| 1 |
| 10 |
所以全程是：
150÷[（1
| 5 |
| 10 |
| 1 |
| 10 |
=150÷（
| 5 |
| 10 |
| 1 |
| 10 |
=150÷
| 2 |
| 5 |
=375（米）．
答：全程为375米．
故答案为：375．
| 3 |
| 3+7 |
| 3 |
| 3+7 |
| 3 |
| 10 |
| 5 |
| 10 |
| 3 |
| 3+7 |
| 3 |
| 10 |
| 3 |
| 10 |
| 1 |
| 10 |
| 5 |
| 10 |
| 1 |
| 10 |
| 5 |
| 10 |
| 1 |
| 10 |
| 2 |
| 5 |