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(0.3-x)(500+100x÷0.1)=120
人气:363 ℃ 时间:2020-02-04 14:54:40
解答
(0.3-x)(500+10x)=120
0.3*500+0.3*10x-500x-10x²=120
150+3x-500x-10x²=120
-10x²-497x+150=120
-10x²-497x+30=0
10x+497x-30=0
a=10,b=497,c=-30 ······
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