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log4^8+log4^2-(1/4)^0 等于多少?
人气:479 ℃ 时间:2020-06-06 21:11:21
解答
log4^8+log4^2-(1/4)^0
=log4^(8*2)-1
=log4^16-1
=log4^(4^2)-1
=2log4^4-1
=2-1
=1
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