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数学
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1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)+...1/(x+2005)(x+2006)=1/2x+4024
人气:106 ℃ 时间:2020-03-29 13:33:56
解答
有等式1/(x+1)(x+2)=1/(x+1)-1/(x+2)
所以左边=1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3).
=1/(x+1)-1/(x+2006)
后面就不用我说了吧 左右移一下统分就可以了
推荐
解方程:x/1*2+x/2*3+…+x/2005*2006=2005
解方程1/(x+1)(x+2)+1/(x+2)(x+3)+.+1/(x+2005)(x+2006)=1/2x+4012
解方程x/1*2+x/2*3+x/3*4+.+x/2205*2006=2005
(x/1×2)+(x/2×3)+(x/3×4)+···+(x/2005×2006)=2005 解方程.
解下列方程: (1)x/1×2+x/2×3+x/3×4+…+x/2005×2006=2 005; (2)4-|3x-4|=2.
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