1,(m-1)x^3+3x^2-nx+x-1=(m-1)x^3+3x^2-(1-n)x-1为二次二项式所以m-1=0且1-n=0  得出：m=1  n=12,x=2代入(m-1)x^3+3x^2-nx+x-1得  8*（m-1)+12-2n+2-1=8m-2n+5=8-2+5=11