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初三数学题(分式化简)
化简:(2009a/a^2-2a+1)/[(1/a-1)+1]
人气:246 ℃ 时间:2020-05-23 19:40:13
解答
(2009a/a^2-2a+1)/[(1/a-1)+1] =2009a/(a-1)^2/[(1+a-1)/(a-1)] =2009a/(a-1)^2*(a-1)/a =2009/(a-1)
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