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a-1/a²+2a+1与6/a²-1通分
人气:124 ℃ 时间:2020-05-07 07:53:33
解答
a-1/a²+2a+1
=(a-1)/(a+1)²
=(a-1)²/[(a-1)(a+1)²]
6/a²-1
=6/[(a+1)(a-1)]
=6(a+1)/[(a-1)(a+1)²]
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