.[（x+4）(x-2)]/x³+2x²+x÷[(x-2)/x·(x+4)/(x+1)]
=[(x+4)*(x-2)]/[x(x+1)^2]/[(x-2)*(x+4)/(x(x+1))]
=(x+4)*(x-2)/[x(x+1)^2]*(x(x+1)/(x-2)*(x+4)
=1/(x+1)
2x/(2x-1)+x/(x-2)=2
2x(x-2)+x(2x-1)=2(x-2)(2x-1)
2x^2-4x+2x^2-x=4x^2-2x-8x+4
5x=4
x=4/5
经检验,X=4/5是方程的解.