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56又11分之8除以9 (2又2/9×4/5+2又2/9x6.2-5.8x2又2/9-1/5÷9/20)x9/20=?的简算法
人气:371 ℃ 时间:2019-12-04 05:25:38
解答
(56+8/11)/9
=6+2/9+8/99
=6又33分之10
(2又2/9×4/5+2又2/9x6.2-5.8x2又2/9-1/5÷9/20)x9/20 2又2/9 =20/9
=(2又2/9×4/5+2又2/9x6.2-5.8x2又2/9-1/5×20/9)x9/20
=20/9(4/5+6.2-5.8-1/5)x9/20
=(0.8-0.2+6.2-5.8)
=1
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