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求导 (1)y=根号2x+sinx (2)y=sinx*Inx (3)y=x/x^2+1 (4)y =In(sinx)
人气:285 ℃ 时间:2019-08-17 19:59:33
解答
(1)y=根号2x+sinx
y'=1/(2√2x)+cosx
(2)y'=cosxlnx+sinx/x
(3)y'=(x^2+1-2x^2)/(x^2+1)^2=(1-x^2)/(x^2+1)^2
(4)y'=cosx/sinx=cotx
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