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化简:1/xy+1/(x+4)(y+4)+1/(x+8)(y+8)+1/(x+12)(y+12)+.1/(x+4n)(y+4n) n为整数
人气:170 ℃ 时间:2020-05-28 13:11:36
解答
1/xy=(1/x-1/y)*(1/y-x)1/(x+4)(y+4)=(1/(x+4)-1/(y+4))*(1/y-x).以此推类提取(1/y-x) 原式=( 1/y-x)*(1/x-1/y+1/(x+4)-1/(y+4).1/(x+4n)-1/(y+4n))因为x=4,y=8所以 原式=(1/4)*( 1/4 -1/8+1/8 -1/12.1/(4+4n) -...
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