计算：[2-(1又2/3-4/5)*2]*(-6又1/3)_数学解答

计算：[2-(1又2/3-4/5)*2]*(-6又1/3)

人气：382 ℃　时间：2020-06-12 03:16:45

解答

[2-(5/3 -4/5)×2]×(-19/3)
=[2-(10/3- 8/5)]×(-19/3)
=[(30/15)-(50/15)+(24/15)]×(-19/3)
=(4/15)×(-19/3)
=-76/45