x(x+1)(x+2)(x+3)=3024[x(x+3)][(x+1)(x+2)]=3024(x^2+3x)(x^2+3x+2)=3024设 x^2+3x =yy(y+2)=3024y^2+2y-3024=0(y+56)(y-54)=0y1= -56y2= 54x^2+3x=-56x^2+3x+56=0(x+ 3/2)^2 -9/4 +56=0(x+ 3/2)^2 + 53.75 =0上面...