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sin10°sin50°-sin50°sin70°-sin70°sin10°=?
请给出过程,谢谢了谢谢!
人气:495 ℃ 时间:2020-02-04 22:08:54
解答
=sin10sin50-sin70sin10-sin50sin70=sin10{sin(60-10)-sin(60+10)}-sin(60-10)sin(60+10)=sin10(-2sin10*cos60)-sin60*sin60cos10*cos10+sin10*sin10cos60*cos60=-sin10*sin10-3/4+sin10*sin10=-3/4
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