如果实数x,y满足2x^2-6xy+9y^2-4x+4=0,那么根号y=
人气：491 ℃ 时间：2019-12-10 17:50:10
解答
因为2x^2-6xy+9y^2-4x+4=0
所以x^2-4x+4+x^2-6xy+9y^2=0
(x-2)^2+(x-3y)^2=0
所以x-2=0,x-3y=0
所以y=2/3
√y=√6/3
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