find the difference between the largest prime number and smallest prime number from 120 to 190.
larget prime number =
smallest prime number =
the requied difference =__________-__________=___________.
for integers that lie between 1 to 10 (excluding 10 itself),subtract the sum of all the prime numbers from the sum of all the composite numbers,find the difference.
composite numbers between 1 and 10:____________________________
prime numbers between 1 and 10:_______________________________
∴
thw difference =___________________________=_______________
人气：339 ℃ 时间：2019-10-19 07:14:08
解答
找出由120到190最大及最小质数差
质数
最大质数 ＝ 181
最小质数 ＝ 127
所要求的相差 ＝ 181 － 127 ＝ 54
在1到10间的整数（不包括10自己）将复合数（非质数）的总和减去质数的总和,找出相差,
1到10间的复合数：4 6 8 9
1到10间的质数：2 3 5 7
∴
相差 （4＋6＋8＋9）－（2＋3＋5＋7）＝10
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