> 数学 >
解分式方程:1/(x2-2x-3) +2/(x2-x-6) +3/(x2+3x+2)=0
人气:150 ℃ 时间:2020-02-06 04:49:10
解答
1/(x2-2x-3) +2/(x2-x-6) +3/(x2+3x+2)=0
1/(x-3)(x+1)+2/(x-3)(x+2)+3/(x+1)(x+2)=0
两边同乘以(x+1)(x+2)(x-3)得:
(x+2)+2(x+1)+3(x-3)=0
x+2+2x+2+3x-9=0
6x=5
x=5/6
推荐
猜你喜欢
© 2026 79432.Com All Rights Reserved.
电脑版|手机版