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计算矩阵的乘积
1 0 0 x1 y1 z1
A= 0 1 2 B= x2 y2 z2
0 1 -2 x3 y3 z3 求A*B=?B*A=?
人气:479 ℃ 时间:2020-01-25 05:41:33
解答
A*B=
x1 y1 z1
x2+2x3 y2+2y3 z2+2z3
x2-2x3 y2-2y3 z2-2z3
B*A=
x1 y1+z1 2y1-2z1
x2 y2+z2 2y2-2z2
x3 y3+z3 2y3-2z3
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