由和差化积公式知：sinx+sinθ=2sin(x+θ)/2cos(x-θ)/2sinx-sinθ=2sin(x-θ)/2cos(x+θ)/2故(sinX+sinθ) .(Sinx-sinθ)=2sin(x+θ)/2cos[(x-θ)/2]2sin(x-θ)/2cos(x+θ)/2=sin(x+θ).sin(x-θ)上面的结论是错的 ...