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1/3+1/15+1/35+1/63+1/99+1/143的简便算法(写过程)
人气:163 ℃ 时间:2020-01-27 20:27:37
解答
原式=1/1*3+1/(3*5)+1/(5*7)+1/(7*9)+1/(9*11)+1/(11*13)
=1/2(1-1/3)+1/2(1/3-1/5)+1/2(1/5-1/7)+1/2(1/7-1/9)+1/2(1/9-1/11)+1/2(1/11-1/13)
=1/2(1-1/13)=6/13
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