根据下列条件求函数f(x)=sin(x+∏/4)+2sin(x-∏/4)-4cos2x+3cos(x+3∏/4)的值 (1)x=∏/4 (2)x=3∏/4
任意角的三角函数计算的
人气:383 ℃ 时间:2020-03-27 05:09:30
解答
(1)x=π/4f(π/4)=sin(π/4+π/4)+2sin(π/4-π/4)-4cos2*π/4x+3cos(π/4+3π/4)=sinπ/2+2sin0-4cosπ/2+3cosπ=1+0-4*0+3*(-1)=-2(2)x=3π/4f(π/4)=sin(3π/4+π/4)+2sin(3π/4-π/4)-4cos2*3π/4x+3cos(3π...
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