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因式分解:①x(x^2+1)-y(y^2+1) ②a^2-b^2+4a+2b+3
人气:139 ℃ 时间:2020-06-24 05:24:57
解答
①x(x^2+1)-y(y^2+1)
=x³-y³+x-y
=(x-y)(x²+xy+y²)+(x-y)
=(x-y)(x²+xy+y²+1)
②a^2-b^2+4a+2b+3
=(a+2)²-(b-1)²
=(a+2+b-1)(a+2-b+1)
=(a+b+1)(a-b+3)
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