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(1)3a2-2a-3+4a2-7a+5;
(2)2(2a-3b)+3(2b-3a);
(3)2a2-[
1
2
(ab-a2)+8ab]-
1
2
ab;
(4)8x2-[-3x-(2x2-7x-5)+3]+4x.
人气:357 ℃ 时间:2020-04-03 23:29:22
解答
(1)原式=7a2-9a+2.
(2)原式=4a-6b+6b-9a
=-5a;
(3)原式=2a2-[
1
2
ab-
1
2
a2+8ab]-
1
2
ab
=2a2-
1
2
ab+
1
2
a2-8ab-
1
2
ab
=
5
2
a2-9ab;
(4)原式=8x2-[-3x-2x2+7x+5+3]+4x
=8x2+3x+2x2-7x-5-3+4x
=6x2-8.
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