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已知sin(x+π/6)=1/3,求sin(5π/6-x)+sin^2(π/3-x)
人气:214 ℃ 时间:2020-04-17 13:48:02
解答
sin(x+π/6)=1/3
sin(5π/6-x)=sin[π-(x+π/6)]=1/3
sin^2(π/3-x)=sin^2[π/2-(x+π/6)]=cos^2(x+π/6)=1-sin^2(x+π/6)=8/9
sin(5π/6-x)+sin^2(π/3-x)=1/3+8/9=11/9
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