> 数学 >
若(x+y-5)^2+lx-y+3l=0
x^2-y^2=?
人气:315 ℃ 时间:2020-06-19 16:45:36
解答
因为 (x+y-5)^2 >=0, lx-y+3l >=0, (x+y-5)^2+lx-y+3l=0
所以 (x+y-5)^2 =0, lx-y+3l =0
所以 x+y = 5, x-y = -3
所以 x^2-y^2 = (x+y)*(x-y) = -15
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版