本题属于复合函数求导!f(x)=1/√(1-x²)f'(x)= [-1/(1-x²)]*[√(1-x²)]'=[-1/(1-x²)] * [(1/2)/√(1-x²)] *[1-x²]'=[-1/(1-x²)] * [(1/2)/√(1-x²)] * -(2x)=x [(1-x²)...