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计算:(a-1/a+1)÷ a^2-2a/a^2-4 × a+1/a^2+3a+2
= =一定要有过程!
人气:179 ℃ 时间:2020-06-24 06:01:13
解答
(a-1/a+1)÷ a^2-2a/a^2-4 × a+1/a^2+3a+2
=(a-1/a+1)* (a+2)(a-2)/ a(a-2) × a+1/(a+1)(a+2)
=(a-1)(a+2)/a(a+1)(a+2)
=(a-1)/ a(a+1)
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