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设f(x)=ax²+bx+c f(x+1)+f(x-1) =2ax²+2bx+2a+2c
人气:188 ℃ 时间:2020-06-29 21:03:49
解答
f(x)=ax²+bx+c
故:f(x+1)+f(x-1)
=a(x+1)²+b(x+1)+c +a(x-1)²+b(x-1)+c
=2ax²+2bx+2a+2c
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