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因式分解:
(1)(2x+y)(2x-3y)+x(2x+y)
(2)8x2(2x2-y2)+y4
人气:439 ℃ 时间:2020-02-03 00:19:37
解答
(1)方法1:(2x+y)(2x-3y)+x(2x+y)
=4x2-6xy+2xy-3y2+2x2+xy,
=6x2-3y2-3xy,
=3(2x2-y2-xy),
=3(2x+y)(x-y).
方法2:(2x+y)(2x-3y)+x(2x+y)
=(2x+y)(2x-3y+x)
=3(2x+y)(x-y).
(2)8x2(2x2-y2)+y4
=16x4-8x2y2+y4
=(4x2-y22
=(2x+y)2(2x-y)2
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