解
原式
=[(x-2)(x+2)/(x-2)²-x/x(x-2)]×(x-4/x)
=[(x+2)/(x-2)-1/(x-2)]×[(x²-4)/x]
=(x+1)/(x-2)×[(x-2)(x+2)/x]
=(x+1)(x+2)/x
=(-1/2+1)(-1/2+2)×(-2)
=-2(1/2)×(3/2)
=-3/2