(2x+1)^5=(2x)^5+5(2x)^4+10(2x)^3+10(2x)^2+5(2x)+1=32x^5+80x^4+80x^3+40x^2+10x+1=ax^5+bx^4+cx^3+dx^2+ex+f对比,得a=32 b=80 c=80 d=40 e=10 f=1a-b+c-d+e-f=32-80+80-40+10-1=1 还可以用简便算法如下：等式对于...