1、因式分解：(x+1)(2x-1)-(2x-1)^2 2、计算：[x(x^2y^2-xy)-y(x^2+x^3y)]÷3x^2y_数学解答

1、因式分解：(x+1)(2x-1)-(2x-1)^2 2、计算：[x(x^2y^2-xy)-y(x^2+x^3y)]÷3x^2y

人气：417 ℃　时间：2019-12-12 09:55:17

解答

1、因式分(x+1)(2x-1)-(2x-1)^2
=(2X-1)［(X+1)-(2X-1)］
=-(2X-1)(X-2)
2、计算：[x(x^2y^2-xy)-y(x^2+x^3y)]÷3x^2y
=［X^2Y(XY-1)-X^2Y(1+XY)］÷3X^2Y
=X^2Y(XY-1-1-XY)÷3X^2Y
=-2/3