f（x）=√3sinxcosx-sin^2x+1/2=√3/2*sin2x-1/2(1-cos2x)+1/2=√3/2sin2x+1/2cos2x =sin(2x+π/6)f(x)最小正周期T=2π/2=π当2x+π/6=2kπ+π/2,k∈Z即x=kπ+π/6,k∈Z时,f(x)取得最大值1f(x)取得...