倾斜角为α的直线过抛物线x^2=10y的焦点f,且与抛物线交于AB两点,若α为锐角,做线段AB的垂直平分线m交y轴于点P,证明|F_数学解答

倾斜角为α的直线过抛物线x^2=10y的焦点f,且与抛物线交于AB两点,若α为锐角,做线段AB的垂直平分线m交y轴于点P,证明|FP|+|FP|cos2α为定值,并求此定值.

人气：479 ℃　时间：2020-06-20 00:41:47

解答

用点差法＋共线.A(x1,y1),B(x2,y2),AB中点M(xo,yo),焦点F(2,0).则有x1+x2=2xo,y1+y2=2yo,又A,B在曲线上有y1^2=8x1,y2^2=8x2,两式相减得AB斜率k=(y1-y2)/(x1-x2)=8/(y1+y2)=4/yo=tana,得yotana=4.又AB,MP共线得k(AB)=...