我在线等已知x=-5,y=1/5.求x^2*x^2n*(y^n+1)^2的值已知x=-5,y=1/5.求x^2*x^2n*(y^n_数学解答

我在线等已知x=-5,y=1/5.求x^2*x^2n*(y^n+1)^2的值
已知x=-5,y=1/5.求x^2*x^2n*(y^n+1)^2的值

人气：496 ℃　时间：2020-05-17 15:53:44

解答

x^2*x^2n*（y^n+1)^2
=x^2*x^2n*（y^n+1)^2
=x^2*x^2n*y^2n*y^2
=(xy)^2(xy)^2n
=(-5*1/5)^2*(-5*1/5)^2n
=1*1
=1