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解下列方程:
(1)(3y+5/3y-6)=1/2+(5y-4/2y-4)
(2)(1/x+4)-(1/x+7)=(1/x+3)-(1/x+6)
人气:232 ℃ 时间:2020-10-01 02:22:34
解答
(1)两边同乘以6(y-2),得
2(3y+5)=3(y-2)+3(5y-4)
6y+10=18y-18
12y=28
y=7/3
(2) 通分:3/((x+4)(x+7))=3/((x+3)(x+6))
(x+4)(x+7)=(x+3)(x+6)
11x+28=9x+18
2x= -10
x= -5
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