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计算(x^2+x-3)/(x^2+x-2)+1=(2x^2+4x+1)/(x^2+2x+1)求出x的值
人气:349 ℃ 时间:2020-02-03 09:12:30
解答
(x^2+x-3)/(x^2+x-2)+1=(2x^2+4x+1)/(x^2+2x+1)
(x^2+x-3)/(x^2+x-2)+1=(2x^2+4x+2-1)/(x^2+2x+1)
(x^2+x-3)/(x^2+x-2)+1=2-1/(x^2+2x+1)
(x^2+x-3)/(x^2+x-2)-1=-1/(x^2+2x+1)
(x^2+x-3-x^2-x+2)/(x^2+x-2)=-1/(x^2+2x+1)
-1/(x^2+x-2)=-1/(x^2+2x+1)
x^2+x-2=x^2+2x+1
x=-3
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