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用sina,cosa表示sin3a,cos3a
人气:363 ℃ 时间:2020-05-22 12:40:57
解答
sin3a=sin2acosa+cos2asina
=2sinacosacosa+[1-2(sina)^2]sina
=-4(sina)^3+3sina.
cos3a=cos2acosa-sin2asina
=[2(cosa)^2-1]cosa-2sinacosasina
=4(cosa)^3-3cosa.
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