> 数学 >
tan(60°-α)tan(30°+α)
怎么算成1?
人气:217 ℃ 时间:2020-10-02 02:30:37
解答
tan(60°-α)tan(30°+α)
=tan(60°-α)cot[90°-(30°+α)]
=tan(60°-α)cot(60°-α)
=tan(60°-α)×1/tan(60°-α)
=1
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版