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lim(x趋于π/4)tan2x*tan(π/4-x)
人气:331 ℃ 时间:2020-06-25 13:02:56
解答
lim(x→π/4) tan2x*tan(π/4-x)=lim(x→π/4) 2tanx/(1-tan^2x)*[tan(π/4)-tan(x)]/[1+tan(π/4)*tan(x)]=lim(x→π/4) 2tanx/(1-tan^2x)*[1-tan(x)]/[1+tan(x)]=lim(x→π/4) 2tanx/(1+tanx)^2=1/2
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