分式方程1/[x(x+1)]+1/[(x+1)(x+2)]+1/[(x+2)(x+3)]+...+1/[(x+9)(x+10)]=5/12
人气：103 ℃ 时间：2020-02-02 21:24:27
解答
即1/x-1/(x+1)+1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+...+1/(x+9)-1/(x+10)=5/121/x-1/(x+10)=5/12两边乘12x(x+10)120=5x²+50xx²+10x-24=0(x+12)(x-2)=0x=-12,x=2
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