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Sint/(1-cost)是如何得于Cot(t/2)的?
中间有个小错误是1-cos2a=[1-(1-2Sin^2a)].
人气:130 ℃ 时间:2020-09-10 03:12:57
解答
令t=2a
a=t/2
则原式=sin2a/(1-cos2a)
=2sinacosa/[1-(1-2sin²a)]
=2sinacosa/2sin²a
=cosa/sina
=cota
=cot(t/2)
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