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f(x)=sin(2x+π/6)+2sin(x-π/4)sin(x+π/4) 怎么化简为形函数
人气:320 ℃ 时间:2020-09-25 06:40:17
解答
f(x)=sin(2x+π/6)+2sin(x-π/4)sin(x+π/4)=sin(2x+π/6)+cos[(x-π/4)-(x+π/4)]-cos[(x-π/4)+(x+π/4)]=sin(2x+π/6)+cos(-π/2)-cos2x=sin(2x+π/6)-cos2x=sin2x*cos(π/6)+cos2x*sin(π/6)-cos2x=sin2x*(√3/...
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