|x+3|-|2x-1|>2x²+1>0
所以：
|x+3|>|2x-1|：x²+6x+9>4x²-4x+1
3x²-10x-8<0
(3x+2)(x-4)<0
-2/3
-2/3
3x+2>2x²+1
2x²-3x-1<0
解得：(3-√17)/4
1/2<=x<4时：
x+3-(2x-1)>2x²+1
2x²+x-3<0
(2x+3)(x-1)<0
-3/2
综上所述,(3-√17)/4
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