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π/2≤x≤π/2时,函数y=sinx+根号3cosx的最大值,最小值,
人气:171 ℃ 时间:2019-08-18 05:45:00
解答
y=2(sinxcosπ/3+cosxsinπ/3)
=2sin(x+π/3)
x=π/6属于[-π/2,π/2],ymax=2
x=-π/2属于[-π/2,π/2],ymin=sin(-π/6)=-1/2
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