sinπ/12-根号3cosπ/12的值
人气:449 ℃ 时间:2020-03-27 12:33:04
解答
原式=2(sinπ/12*1/2-cosπ/12*√3/2)
=2(sinπ/2cosπ/3-cosπ/12sinπ/3)
=2sin(π/12-π/3)
=2sin(-π/4)
=-√2
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