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数学
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1/(√3+2)如何化简
人气:275 ℃ 时间:2020-04-11 07:18:00
解答
(1/(√3+2))*(√3-2)/√3-2)=(√3-2)/(3-4)=2-√3(√3-2)/(3-4)=2-√3怎么得来的(1/(√3+2))*((√3-2)/√3-2)=(√3-2)/((√3-2)*(√3+2))=(√3-2)/(3-4)=√3-2)/-1=2-√3
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